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## What is the value of the `x` variable at the end of the following snippet?

```float x;
x = 1. / 2 * 3;
/***```
• `1.5`
• `1`
• `2`
• 0
 Explanation & Hints: To determine the value of the `x` variable in the given snippet, we need to evaluate the expression `x = 1. / 2 * 3;`. Here, the expression involves: `1.` which is a floating-point number equivalent to `1.0`. Division by `2`, resulting in `1.0 / 2 = 0.5`. Multiplication of the result by `3`, leading to `0.5 * 3 = 1.5`. Thus, the value of `x` at the end of this snippet will be `1.5`.

## What is the value of the `x` variable at the end of the following snippet?

```int x;
x = 1 / 2;```
• `0`
• `1`
• `2`
• `0.5`
 Explanation & Hints: Let’s break down the assignment: ```int x; x = 1 / 2;``` `1 / 2` is an integer division. Since both `1` and `2` are integers, the result is also an integer. `1 / 2` equals `0` in integer division because the fractional part (0.5) is discarded. So, the value of `x` at the end of the snippet is 0.

## What is the value of the `x` variable at the end of the following snippet?

```int x;
x = 1 / 2 * 3;
/* */```
• `0`
• `1`
• `2`
• `1.5`
 Explanation & Hints: Let’s break down the operations step-by-step: int x; x = 1 / 2 * 3; In C, the operations are performed from left to right due to the same precedence level (both `/` and `*` have the same precedence and associate left to right): Integer division: `1 / 2` is an integer division. Since both `1` and `2` are integers, the result is also an integer. `1 / 2` equals `0` in integer division because the fractional part (0.5) is discarded. Multiplication: The result of the division (`0`) is then multiplied by `3`. `0 * 3` equals `0`. So, the value of `x` at the end of the snippet is 0.

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