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  • Post last modified:June 12, 2024

Analyze the code snippet:

let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);

After its execution, the variables x, y, and z will have the values:

  • x: false, y: true, z: 1
  • x: null, y: null, z: 1
  • x: true, y: false, z:1
  • x: 1, y: 1, z: 1
Answers Explanation & Hints:

After executing the code snippet:

let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);

The variables x, y, and z will have the following values:

  • x will have a value of false.
  • y will have a value of true.
  • z will have a value of 1.

Let’s break down the code snippet step by step:

  1. The variable nr is assigned the string value "1".
  2. The variable x is assigned the result of the comparison nr === 1. Since nr is a string and 1 is a number, the strict equality operator (===) compares both the value and the type. In this case, the types are different, so the result is false.
  3. The variable y is assigned the result of the comparison nr == 1. The loose equality operator (==) performs type coercion, trying to convert the operands to a common type before comparing. In this case, the string "1" is coerced to the number 1, resulting in a true comparison.
  4. The variable z is assigned the value 1. However, it’s important to note that the expression (nr = 1) is an assignment operation. It assigns the value 1 to the variable nr and also evaluates to the assigned value. Therefore, nr is updated to 1, and z is assigned the value of nr, which is 1.

To summarize:

  • x has a value of false.
  • y has a value of true.
  • z has a value of 1.

To illustrate this in code:

let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);

console.log(x); // Output: false
console.log(y); // Output: true
console.log(z); // Output: 1

So, the correct answer is:

x: false, y: true, z: 1

For more Questions and Answers:

JavaScipt Essentials 1 (JSE) | JSE1 – Module 3 Test Exam Answers Full 100% 

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