Analyze the code snippet:
let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);
After its execution, the variables x
, y
, and z
will have the values:
- x:
false
, y: true
, z: 1
- x:
null
, y: null
, z: 1
- x:
true
, y: false
, z:1
- x:
1
, y: 1
, z: 1
Answers Explanation & Hints:
After executing the code snippet:
let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);
The variables x , y , and z will have the following values:
x will have a value of false .
y will have a value of true .
z will have a value of 1 .
Let’s break down the code snippet step by step:
- The variable
nr is assigned the string value "1" .
- The variable
x is assigned the result of the comparison nr === 1 . Since nr is a string and 1 is a number, the strict equality operator (=== ) compares both the value and the type. In this case, the types are different, so the result is false .
- The variable
y is assigned the result of the comparison nr == 1 . The loose equality operator (== ) performs type coercion, trying to convert the operands to a common type before comparing. In this case, the string "1" is coerced to the number 1 , resulting in a true comparison.
- The variable
z is assigned the value 1 . However, it’s important to note that the expression (nr = 1) is an assignment operation. It assigns the value 1 to the variable nr and also evaluates to the assigned value. Therefore, nr is updated to 1 , and z is assigned the value of nr , which is 1 .
To summarize:
x has a value of false .
y has a value of true .
z has a value of 1 .
To illustrate this in code:
let nr = "1";
let x = (nr === 1);
let y = (nr == 1);
let z = (nr = 1);
console.log(x); // Output: false
console.log(y); // Output: true
console.log(z); // Output: 1
So, the correct answer is:
x: false, y: true, z: 1
|
For more Questions and Answers: