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  • Post last modified:June 12, 2024

Analyze the code snippet:

let n = 10;
let m = ++n;

Its execution will result in the following values in the variables n and m:

  • n: 11, m: 10
  • n: 10, m: 11
  • n: 11, m: 11
  • n: 10, m:10
Answers Explanation & Hints:

The execution of the code snippet let n = 10; let m = ++n; will result in the following values in the variables n and m:

  • n will have a value of 11.
  • m will also have a value of 11.

Let’s break down the code snippet step by step:

  1. Initially, the variable n is assigned the value of 10.
  2. The ++ operator before the variable n is the pre-increment operator. It increments the value of n by 1 before using it.
  3. Therefore, when ++n is executed, the value of n is incremented to 11.
  4. The value of n (which is now 11) is then assigned to the variable m.

After the code snippet is executed, n will be 11 and m will also be 11.

To illustrate this in code:

let n = 10;
let m = ++n;
console.log(n); // Output: 11
console.log(m); // Output: 11

So, the resulting values in the variables n and m will be 11 for both.

For more Questions and Answers:

JavaScipt Essentials 1 (JSE) | JSE1 – Module 3 Test Exam Answers Full 100% 

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