• Post author:
  • Post category:Blog
  • Reading time:4 mins read
  • Post last modified:June 12, 2024

Analyze the following code:

let x 10;
console.log(x);

What exception will be thrown as a result of its execution attempt?

  • TypeError
  • RangeError
  • ReferenceError
  • SyntaxError
Explanation & Hint:

The code contains a syntax error. In the line let x 10;, there is a missing assignment operator (=) between x and 10, which leads to a syntax error.

For more Questions and Answers:

JavaScript Essentials 1 | JSE1 – Module 6 Test Exam Answers Full Score 100%

 

Analyze the following code:

let x = 10;
ocnsole.log(x);

What exception will be thrown as a result of its execution attempt?

  • SyntaxError
  • ReferenceError
  • TypeError
  • RangeError
Explanation & Hint:

JavaScript interpreter will throw a ReferenceError and display an error message indicating that ocnsole is not defined. The error occurs because the interpreter cannot find a variable or function named ocnsole, and it is unable to execute the code as intended.

For more Questions and Answers:

JavaScript Essentials 1 | JSE1 – Module 6 Test Exam Answers Full Score 100%

 

Analyze the following code:

const x = 10;
onsole.log(x);
x += 10;

What exception will be thrown as a result of its execution attempt?

  • ReferenceError
  • SyntaxError
  • ReferenceError and TypeError
  • TypeError
Explanation & Hint:

If you attempt to execute the code with the errors (onsole.log(x) and x += 10;), the JavaScript interpreter will throw a ReferenceError. The ReferenceError will occur due to the typo in onsole.log(x). The error message will indicate that onsole is not defined.

For more Questions and Answers:

JavaScript Essentials 1 | JSE1 – Module 6 Test Exam Answers Full Score 100%

 

Analyze the following code:

const x = 10;
x = 20;

What exception will be thrown as a result of its execution attempt?

  • ReferenceError
  • TypeError
  • RangeError
  • SyntaxError
Explanation & Hint:

If you attempt to execute the code the JavaScript interpreter will throw a TypeError. The TypeError will occur because you are trying to reassign a value to a constant variable, which is not allowed. Constants are immutable and their values cannot be changed once assigned.

For more Questions and Answers:

JavaScript Essentials 1 | JSE1 – Module 6 Test Exam Answers Full Score 100%

Subscribe
Notify of
guest
0 Comments
Newest
Oldest Most Voted
Inline Feedbacks
View all comments