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  • Post last modified:June 12, 2024

Analyze the following code:

let show = function () {
     console.log("test");}
setTimeout(show, 2000);

What happens when you execute it?

  • The console to display test after a 2000-second delay.
  • The console to display show after a 2-second delay.
  • The console to display test after a 2-second delay.
  • The console to display test 2000 times.
Explanation & Hint:

When you execute the code, the following sequence of events will occur:

  1. A variable named show is declared and assigned a function expression. This function has no parameters and contains a single statement that logs the string “test” to the console using console.log(“test”).
  2. The setTimeout function is called with two arguments: the show function and a delay of 2000 milliseconds (2 seconds).
  3. The setTimeout function is a built-in JavaScript function that schedules the execution of a function after a specified delay. In this case, it schedules the execution of the show function after a 2-second delay.
  4. After 2 seconds have elapsed, the JavaScript runtime environment triggers the execution of the show function.
  5. The show function is executed, and the string “test” is logged to the console using console.log(“test”).

In summary, when you execute the code, it schedules the execution of the show function to occur after a 2-second delay using setTimeout. After the specified delay, the function is executed, and “test” is displayed in the console.

For more Questions and Answers:

JavaScript Essentials 1 | JSE1 – Module 5 Test Exam Answers Full Score 100%

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