Advanced operations on arrays and pointers, memory management, and the basics of functions M5 Test

Advanced operations on arrays and pointers, memory management, and the basics of functions M5 Test

Advanced operations on arrays and pointers, memory management, and the basics of functions M5 Test

  1. What happens if you try to compile and run this program?

    #include <stdio.h>

int main(void)
{
      char *p = "12345", *q = p - 10;
     
      printf("%d",'1[14] - q[13]);
      return 0;
}
    • the program outputs 1
    • the program outputs 2
    • the program outputs 3
    • the program outputs 4

  2. What happens if you try to compile and run this program?

    #include <stdio.h>

int main(void)
{
      int i = 0;
      i = f(f(i));
     
      printf("%d",i);
      return 0;
}
    • the program outputs 2
    • the program outputs 1
    • the program outputs 0
    • the compilation fails

  3. What happens if you try to compile and run this program?

    #include <stdio.h>

int f(int 1)
{
      ++i;
      return i;
}
int main(void)
{
     int i = 1;
     i = f(i);     
          printf("%d",i);
      return 0;
}
    • the program outputs 2
    • the program outputs 1
    • the program outputs an unpredictable value
    • the compilation fails

  4. What happens if you try to compile and run this program?

    #include <stdio.h>

int main(void)
{
      int i = 0;
      i = f(f(i));
     
      printf("%d",i);
      return 0;
}
    • the compilation fails
    • the program outputs nul
    • the program outputs NULL
    • the program outputs 0

  5. What happens if you try to compile and run the program?

    #include <stdio.h>
int main(void)
{
  int i = 0;
    { 
      int i = 1;
      main.i = i;
    }
  printf("%d",i);
  return 0;
}
    • the compilations fails
    • the program outputs 1
    • the program outputs 2
    • the program outputs 0

  6. What happens if you try to compile and run program?

    #include <stdio.h>
int f(int i) {
    return ++i;
}
int main(void)
{
  int i = 0;
  i = f(f(i));
  printf("%d", i);
  return 0;
}
    • the program outputs 2
    • the program outputs 1
    • the program outputs 0
    • the compilations fails

  7. What happens if you try to compile and run program?

    #include <stdio.h>
#include <stdlib.h>
int main(void)
{
  int t[] = {8, 4, 2, 1};
  int *p = (int*)malloc(sizeof(t));
  int i;
  for(i = 0; i<4; i++)
     p[3 -i] = t[i];
  printf("%d", *(p + 2));
  free(p);
  return 0;
}
    • the program outputs 4
    • the program outputs 2
    • the program outputs 3
    • the program outputs 1

  8. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
  int t[] = {1, 2, 3, 4, 5}, * p = t;

  *p++;
  (*p)++;
  *p++;

  printf("%d", p[-1]);
  return 0;
}
    • the program outputs 3
    • the program outputs 1
    • the program outputs 2
    • the program outputs 4

  9. What happens if you try to compile and run program?

    #include <stdio.h>
#include <stdlib.h>
int main(void)
{
  int i,j;
  int **p = (int **) malloc(2* sizeof(int *));
  p[0] = (int *) malloc (2 * sizeof(int));
  p[1] = p[0];
  for(i = 0; i < 2; i++)
     for(j = 0; j <2; j++)
        p[i][j] = i + j;
           printf("%d", p[0][0]);
     return 0;
}
    • the program outputs 1
    • the program outputs 3
    • the program outputs 4
    • the program outputs 2

  10. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
  int t[1][2][2] = {{{1,2},{3,4}}};

    int s = 0, i,j,k;

  for(i = 1; i > 0; i -=2)
     for(j = 1; j < 2; j += 2)
         for(k = 0; k < 3; k += 3)
             s += t[k][i - 1][j];
  printf("%d",s);
  return 0;         
}
    • the program outputs 1
    • the program outputs 2
    • the program outputs 3
    • the program outputs 4

  11. What happens if you try to compile and run program?

    # include <stdio.h>
int main(void)
{
   int *t [10];
   int (*u) [10];
   printf("%d", sizeof(t) != sizeof(u));
   return 0;
}
    • the program outputs 1
    • the program outputs 0
    • the program outputs 4
    • the program outputs 16

  12. What happens if you try to compile and run program?

    #include <stdio.h>
int f(int i){
    i++;
}
int main(void)
{
    int i = 1;
    f(i);
   printf("%d", i);
   return 0;
}
    • the program outputs 1
    • the program outputs 2
    • the program outputs an unpredictable value
    • the compilation fails

  13. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
  char s[] = "ABCDE", *p = s + 5;
  printf("%d", p[-1] - *(p - 4));
  return 0;
}
    • the program outputs 3
    • the program outputs 4
    • the program outputs 2
    • the program outputs 1

  14. What happens if you try to compile and run program?

    #include <stdio.h>
int f(void){
}
int main(void){
   int i;  
   i = f();
   printf("%d", i);
   return 0;
}
    • the program outputs an unpredictable value
    • the program outputs 0
    • the program outputs NULL
    • the compilation fails

  15. What happens if you try to compile and run program?

    #include <stdio.h>
#include <stdlib.h>
int main(void)
{
   int i,j;
   int **p = (int **)malloc(2 * sizeof(int *));
   p[0] = (iny *)malloc(2 * sizeof(int));
   p[1] = (int *)malloc(2 * sizeof(int));

   for(i = 0; i < 2; i++)
      for(j = 0; j < 2; j++;
         p[i][j] = i + j; 
   printf("%d", p[0][0]);
   return 0;
}
    • the program outputs 0
    • the program outputs 1
    • the program outputs 2
    • the program outputs 3

  16. What happens if you try to compile and run program?

    #include <stdio.h>

void f(int i){
   i++;
}
int main(void)
{
   int i = 1;
   
   f(i);
   printf("%d", 1);
   return 0;
}
    • the program outputs 1
    • the program outputs 2
    • the program outputs  an unpredictable value
    • the compilation fails

  17. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
  int t[2][2] = { 1, 2, 4, 8};

  int s =  0, i, j;

  for(i = 2; i; i -= 2)
     for(j = 1; j < 2; j += 2)
        s += t[i - 1][j];
  printf("%d", s);
  return 0;
}
    • the program outputs 8
    • the program outputs 2
    • the program outputs 4
    • the program outputs 1

  18. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
   int *(t[10]);
   int *u[10];
   printf("%d", sizeof(t) != sizeof(u));
   return 0;
}
    • the program outputs 0
    • the program outputs 1
    • the program outputs 3
    • the program outputs 2

  19. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
   char s[10] = "ABCDE", *p = s + 3;
   printf("%d", p[1] - p[-1]);
   return 0;
}
    • the program outputs 2
    • the program outputs 1
    • the program outputs 3
    • the program outputs 4

  20. What happens if you try to compile and run program?

    #include <stdio.h>
int main(void)
{
   int *p = (int *)malloc(2 * sizeof(int));

   *p = 2;
   *(p + 1) = *(p) - 1;
   *p = p[1];
   printf("%d", *p);
   free(p);
   return 0;
}
    • the program outputs 1
    • the program outputs 2
    • the program outputs 3
    • the program outputs 4