Preprocessor and declarations M8 Test

Preprocessor and declarations M8 Test

Preprocessor and declarations M8 Test

  1. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA(x, y)  x+y

int main(void){
    int i = -1;
    int i2 = -2;

    printf("%d", -ALPHA(i i2));
    return 0;
}
    • the program outputs -1
    • the program outputs -2
    • the program outputs -3
    • the program outputs 0

  2. What happens if you try to compile and run this program?

    #include <stdio.h>
#define A(x) ((x)?-1:0)
#define B(a) !(a)

int main(void) {
    int i = 2;
    int i2 = A(B(i));

    printf("%d", i2);
    return 0;
}
    • the program outputs -1
    • the program outputs -3
    • the program outputs -2
    • the program outputs 0

  3. What happens if you try to compile and run this program?

    #include <stdio.h>

int main(void) {
    int X = 1;
#define X 1
    int Y = X - 2;
#undef X
    printf("%d", Y+X);
    return 0;
}
    • the program outputs -1
    • the program outputs -3
    • the program outputs 0
    • the program outputs -2

  4. What happens if you try to compile and run this program?

    #include <stdio.h>
#define X 1
#define y 2

int main(void) {
    int i =
#if X << Y > 0
    -X
#else
    -Y
#endif
    ;
    printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs 0
    • the program outputs -2
    • the program outputs -1

  5. What happens if you try to compile and run this program?

    #include <stdio.h>
#define X 1
#define y 2

int main(void) {
    int i =
#if X >> Y > 0
    -X
#else
    -Y
#endif
    ;
    printf("%d", i);
    return 0;
}
    • the program outputs -2
    • the program outputs -1
    • the program outputs 0
    • the program outputs -3

  6. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA -2

int main(void) {
    int i = -1;
i += ALPHA;

        printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs -1
    • the program outputs -2
    • the program outputs 0

  7. What happens if you try to compile and run this program?

    #include <stdio.h>

int main(void) {
#undef X
    int X = 1;
    int Y = X - 2;

#define X -2
    printf("%d",Y+X);
    return 0;
}
    • the program outputs -1
    • the program outputs -2
    • the program outputs 0
    • the program outputs -3

  8. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA -1+2

int main(void) {
    int i = -1;
    i += ALPHA;
    printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs 0
    • the program outputs -1
    • the program outputs -2

  9. What happens if you try to compile and run this program?

    #include <stdio.h>
#define X 1
#define y 2

int main(void) {
    int i = -1;
    i = -1 * ALPHA;

    printf("%d", i);
    return 0;
}
    • the program outputs 0
    • the program outputs -3
    • the program outputs -1
    • the program outputs -2

  10. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA(x)    2*-x

int main(void) {
    int i = ALPHA((1-1));

    printf("%d", i);
    return 0;
}
    • the program outputs 0
    • the program outputs -1
    • the program outputs -3
    • the program outputs -2

  11. What happens if you try to compile and run this program?

    #include <stdio.h>
#define A
#define C

int main(void) {
    int i =
#ifdef A 
#ifdef B
    -1
#else
    -2
#endif
#else
    -3
#endif
    ;

    printf("%d", i);
    return 0;
}
    • the program outputs -1
    • the program outputs -2
    • the program outputs -3
    • the program outputs 0

  12. What happens if you try to compile and run this program?

    #include <stdio.h>
#define B
#define C

int main(void) {
    int i =
#ifdef A 
#ifdef C
    -1
#else
    -2
#endif
#else
    -3
#endif
    ;

    printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs -1
    • the program outputs -2
    • the program outputs 0

  13. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA(x, y) x##2-y

int main(void) {
    int i = -1;
    int i2 = -2;

    printf("%d", ALPHA(i, i2));
    return 0;
}
    • the program outputs -1
    • the program outputs -2
    • the program outputs 0
    • the program outputs -3

  14. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA -1-2

int main(void) {
    int i = -1;
    i = i * ALPHA;

    printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs 0
    • the program outputs -2
    • the program outputs -1

  15. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA(x) -x

int main(void) {
    int i = ALPHA(2-1);
    printf("%d", i);
    return 0;
}
    • the program outputs 0
    • the program outputs -1
    • the program outputs -3
    • the program outputs -1

  16. What happens if you try to compile and run this program?

    #include <stdio.h>
#define A
#define C

int main(void) {
    int i =
#ifdef A
#ifdef C
    -1
#endif
#else
    -3
#endif
    ;

    printf("%d", i);
    return 0;
}
    • the program outputs -1
    • the program outputs -3
    • the program outputs 0
    • the program outputs -2

  17. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA(x) 2*-x

int main(void) {
    int i = ALPHA(1-);

    printf("%d", i);
    return 0;
}
    • the program outputs -2
    • the program outputs 0
    • the program outputs -3
    • the program outputs -1

  18. What happens if you try to compile and run this program?

    #include <stdio.h>
#define ALPHA -1
#define BETA - ALPHA

int main(void) {
    int i = ALPHA + BETA * ALPHA * BETA;
    printf("%d", i);
    return 0;
}
    • the program outputs -3
    • the program outputs -2
    • the program outputs 0
    • the program outputs -1

  19. What happens if you try to compile and run this program?

    #include <stdio.h>
#define A(x)  ((x)?-1:0)

int main(void) {
    int i = 2;
    int i2 = A(i) * i;
    printf("%d", i2);
    return 0;
}
    • the program outputs -2
    • the program outputs -3
    • the program outputs -1
    • the program outputs 0

  20. What happens if you try to compile and run this program?

    #include <stdio.h>
#define A(x) #x

int main(void) {
    int i = -1;
    char *s = A(i);
    i = -(s[0] == 'i';

    printf("%d", i);
    return 0;
}
    • the program outputs 0
    • the program outputs -3
    • the program outputs -1
    • the program outputs -2