Advanced C++ | Final Test

CPP : All Parts

CPP – Advanced Programming in C++ : All Parts
M1	M4	M7
M2	M5	M8
M3	M6	M9
Summary Test
Final Test

What happen if you try to compile and run this program?

#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<iomanip>
#include<fstream>
using namespace std;
void
printer (int i)
{
  cout <<setw(2) << i <<", ";
}

int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  vector<int> v1 (mynumbers, mynumbers + 6);
  fstream outfile("output.txt", ios::trunc | ios::out);
  int i = 0;
  while(i > 1); //LINE I
  {
    outfile >> i; //LINE II
    i = v1[0];
    v1.pop_back();
  }
  outfile.close();
  for_each(v1.begin(), v1.end(), printer);
  outfile.close();
  outfile.open("output.txt");
  return 0;
}

runtime error at LINE I
the program outputs 4, 6, 7, 8, 9,
compilation error in LINE II
program run forever without output
the program outputs 8, 9, 7, 6, 4, 1,
compilation error in LINE I
the program outputs 8, 9, 7, 6, 4,

Which methods from std::deque class can be used to check if there are element in the container. Choose all that apply:
- clear()
- isfull()
- empty()
- there is no such method
- isempty()
- size()

What will happen when you attempt to compile and run the following code?

#include<vector>
#include<iostream>
#include<algorithm>
using namespace std;
class Pocket
{
   int value;
public:
   Pocket(int value): value(value){}
   int getValue()const
   {
     return value;
   }
   bool operator < (const Pocket & _Right) const
   {
     return value < _Right.value;
   }
};
bool
operator == (Pocket & _Left, int _Right)
{
    return(_Left.getValue() == _Right);
}
ostream & operator << (ostream & stream, const Pocket & pocket)
{
   stream << pocket.getValue();
   return stream;
}
void
printer (Pocket i)
{
   cout << i << ", ";
}
int
main()
{
    int mynumbers[] = {8, 9, 7, 6, 4, 1};
    vector<Pocket> v1 (mynumbers, mynumbers + 6);
    sort (v1.begin(), v1.end()); //LINE I
    remove(v1.begin(), v1.end(), 2); //LINE II
   for_each(v1.begin(), v1.end(), printer);
   return 0;
}

compilation error in LINE II
runtime error at LINE I
the program outputs 1, 4, 6, 7, 8, 9,
the program outputs 8, 9, 7, 6, 4, 1,
compilation error in LINE I
the program outputs 1, 4, 7, 8, 9,

What happen if you try to compile and run this program?

#include<vector>
#include<iostream>
#include<algorithm>
#include<functional>
using namespace std;
void
printer(int i)
{
   cout << i << ", ";
}

int
main()
{
  int mynumbers1[] = {8, 9, 7, 6, 4, 1};
  int mynumbers2[] = {7, 8, 7, 4, 5, 1};
  vector<int> v1 (mynumbers1, mynumbers1 + 6);
  vector<int> v2 (mynumbers1, mynumbers1 + 6);
  vector<int> v3 (mynumbers2, mynumbers2 + 6); //LINE I
  transform(v1.begin(), v1.end(), v2.rbegin(), v3.begin(), minus<int>()); //LINE II
  for_each(v3.rbegin(), v3.rend(), printer);
  return 0;
}

compilation error in LINE I
the program outputs 1, 1, 0, 2, -1, 0,
the program outputs -7, -5, -1, 1, 5, 7,
runtime error at LINE I
the program outputs 0, -1, 2, 0, 1, 1
compilation error in LINE II

What will happen when you attempt to compile and run the following code?

#include<vector>
#include<iostream>
#include<algorithm>
using namespace std;
class Pocket
{
  int value;
public:
   Pocket(int value): value(value){}
   int getValue()const
  {
    return value;
  }
  bool operator < (const Pocket & _Right) const
  {
    return value < _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
 {
    stream << pocket.getValue();
    return stream;
  }
void
printer (Pocket i)
{
   cout << i << ", ";
}
int
main()
{
   int mynumbers1[] = {8, 9, 7, 6 };
   int mynumbers2[] = {4, 1, 4, 5 };
   vector<Pocket> v1(7, 0);
   sort (mynumbers2, mynumbers2 + 4);
   copy (mynumbers1, mynumbers1 + 3, v1.begin ());
   copy (mynumbers2, mynumbers2 + 3, v1.begin () + 3);
   sort (mynumbers1, mynumbers1 + 4);  //LINE I
   inplace_merge (v1.begin (), v1.begin() + 4, v1.end());  //LINE II
   for_each(v1.begin(), v1.end(), printer);
   return 0;
}

compilation error in LINE II
runtime error at LINE I
you shouldn’t call inplace_merge function on non ordered v1 vector;;;;
the program outputs 4, 4, 0, 8, 9, 7, 1,
compilation error in LINE I
the program outputs 4, 4, 0, 8, 9, 7,
the program outputs 4, 4, 8, 9, 7, 1,

What will happen when you attempt to compile and run the following code?

#include<vector>
#include<iostream>
#include<set>
#include<deque>
#include<algorithm>
using namespace std;
template class T > struct Out
{
  ostream & out;
  Out (ostream & o):out(o){}
  void operator () (const T& val)
  {
    out << val << ", ";
   }
};
struct Sequence
{
  int start;
  Sequence (int start):start (start){}
  int operator () ()
  {
     return start++ % 7;
   }
};
int
main()
{
  vector < int > v1(3);
  generate (v1.begin (),v1.end (), Sequence (10));   //LINE I
  set < int >s1(v1.rbegin (), v1.rend ());
  deque < int > d1(s1.rbegin (), s1.rend ());
  reverse (v1.begin ()v1.end ());
  reverse (d1.begin (),d1.end ());   //LINE II
  for_each(s1.begin(),s1.end(), Out < int >(cout));
  for_each(d1.begin(),d1.end(), Out < int >(cout));
  return 0;
}

compilation error in LINE I
the program outputs 3, 4, 5, 5, 4, 3,
the program outputs 3, 4, 5, 3, 4, 5, 3, 4, 5,
runtime error at LINE I
compilation error in LINE II
the program outputs 3, 4, 5, 3, 4, 5,

What happen if you try to compile and run this program?

#include<iomanip>
#include<iostream>
using namespace std;
int
main()
{
  double goodpi = 3.141593;
  double badpi = 3.5;
  cout << goodpi << ", ";
  cout << setprecision (3);  //LINE I
  cout << goodpi << ", ";    //LINE II
  cout << badpi<< ", ";
  return 0;
}

the program outputs 3.14159, 3.14, 3.50,
the program outputs 3.14159, 3.140, 3.500,
compilation error in LINE II
the program outputs 3.14159, 3.14, 3.5,
runtime error at LINE I
compilation error in LINE I

What happen if you try to compile and run this program?

#include<iostream>
using namespace std;
template < class T > void
f (T & a)       //LINE I
{
   cout << 1 + a << end1;
}
int
main()
{
  double a = 1.5;
  f < float & > (a);      //LINE II
  return 0;
}

compilation error in LINE II
the program outputs 1.5
the program outputs 2.5
compilation error in LINE I
the program outputs 2
runtime error at LINE I

What happen if you try to compile and run this program?

#include<iostream>
#include<set>
#include<vector>
using namespace std;
int
main()
{
  int mynumbers[] = { 8, 9, 7, 6, 4, 1 };
  vector < int >v (mynumbers, mynumbers + 6);
  set < int >s1 (v.begin (), v.end());
  s1.erase (s1.lower_bound (4), s1.upper_bound (9));   //LINE I
  s1.insert (10);      //LINE II
  s1.insert (v.begin (), v.end());
  for (set < int >::iterator i = s1.begin (); i != s1.end (); i++)
     cout << *i <<", ";
  return 0;
}

compilation error in LINE II
program outputs: 1, 4, 6, 7, 8, 9,
program outputs: 1, 4, 6, 7, 8, 9, 10,
program outputs: 1, 4, 9, 10,
runtime error at LINE II
program outputs: 1, 10,
compilation error in LINE I

What happen if you try to compile and run this program?

#include<vector>
#include<iostream>
#include<algorithm>
using namespace std;
void
printer (int i)
{
  cout << i << ", ";
}
int
main()
{
  int mynumbers1[] = { 8, 9, 7, 6 };
  int mynumbers2[] = { 4, 1, 4, 5 };
  vector < int >v1 (3);
  sort (mynumbers2, mynumbers2 + 3);
  sort (mynumbers1, mynumbers1 + 3); //LINE I
  set_symmetric_difference (mynumbers1, mynumbers1 + 1, mynumbers2,
  mynumbers2 + 2, v1.begin ()); //LINE II
  for_each (v1.begin (), v1.end(), printer);
  return 0;
}

compilation error in LINE II
program outputs 1, 4, 7,
program outputs 1, 4, 4,
runtime error at LINE II
program outputs1, 4, 7, 0, 0,
compilation error in LINE I
runtime error at LINE I

What happen if you try to compile and run this program?

#include<vector>
#include<iostream>
#include<algorithm>
#include<functional>
using namespace std;
struct Add:public binary_function < int, int, int >
{
  int operator () (const int &_Left, const int &_Right) const //LINE I
  {
    return _Left + _Right;
  }
};

void
printer (int i)
{
  cout << i << ", ";
}
int
main()
{
  int mynumbers[] = { 8, 9, 7, 6, 4, 1 };
  vector < int >v1 (mynumbers, mynumbers + 6);
  vector < int > v2 (7);
  transform (v1.begin (), v1.end (), v2.begin (), bind1st (Add (), -1)); //LINE II
  for_each (v2.rbegin (), v2.rend(), printer);
  return 0;
}

runtime error at LINE I
the program outputs 0, 3, 5, 6, 8, 7,
runtime error at LINE II
the program outputs0, 0, 3, 5, 6, 8, 7,
compilation error in LINE I
compilation error in LINE II
the program outputs7, 8, 6, 8, 7,

Which of the following is are legal variable names?

#include<vector>
#include<iostream>
#include<string>
using namespace std;
template < typename T > ostream & print (const T & start, const T & end)
{
  T tmp = start;
  for (; tmp != end; ++tmp)
  {
    cout << *tmp << " "; //LINE I
  }
  return cout;
}
class A
{
public:
  int a;
public:
  A (int a):a (a) {}
};
ostream & operator<< (ostream & c, const A & o)
{
  c << o.a;
  return c;
}
int
main()
{
  int tab[] = { 1, 5, 3, 3, 5, 6 };
  vector < A >v1 (tab, tab + 6); //LINE II
  v1.insert (v1.end (), A (0));
  print (v1.begin (), v1.end()) << endl;
  return 0;
}

compilation error in LINE I
compilation error in LINE II
runtime error at LINE II
program outputs: 1, 5, 3, 3, 5, 6, 0,
program outputs: 1, 5, 3, 3, 5, 6, 1
program outputs: 1, 5, 3, 3, 5, 6,

What happen if you try to compile and run this program?

#include<iostream>
#include<map>
#include<vector>
#include<sstream>
#include<string>
using namespace std;
int
main()
{
  int mynumbers[] = { 3, 9, 3, 2, 1, 4, 5 };
  vector < int >v (mynumbers, mynumbers + 7);
  map < int, string > m;
  for (vector < int >::iterator i = v.begin(); i != v.end(); i++)
  {
    stringstream s;
    s << *i;
    m.insert(pair<int, string>(*i, s.str()));
  }
  pair<map<int, string>:: iterator, map<int, string> :: iterator> range;
  range = m.equal_range(3);
  map<int, string>::iterator i = range.first; //LINE I
  for(; i != range.second; i++)
  {
    cout << i->second <<", "<<i->first<<", ";
  }
  return 0;
}

runtime error at LINE I
program outputs: 3, 3, 9, 9, 3, 3,
program outputs: 3, 3,
compilation error in LINE I
program outputs: 0, 0, 3, 3,

What happen if you try to compile and run this program?

#include<iostream>
using namespace std;
class SomethingSpecial
{
public:
  double value;

  SomethingSpecial ():value (0){}
  SomethingSpecial (double value):value (value){}
  SomethingSpecial operator+= (SomethingSpecial & _Right)
  {
    SomethingSpecial result;
    result.value = value + _Right.value;
  }
};
template < typename T > class Pocket
{
  T value;
public:
    Pocket(){}
  Pocket (T value);
T getValue ()
{
  return value;
}
void add (T _Right)
{
  value += _Right;
}
};
template < class T > Pocket < T >::Pocket (T value):value (value){}
int
main()
{
  Pocket < double >a (3); //LINE I
  Pocket < SomethingSpecial > n;
  n.add(SomethingSpecial ()); //LINE II
  cout << a.getValue () << ", ";
  a.add (3);
  cout << a.getValue ();
  return 0;
}

compilation error in LINE I
runtime error at LINE I
program outputs: 3, 6,
program outputs: 6, 6,
compilation error in LINE II
program outputs: 3, 3,

What happen if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
void
printer(int i)
{
  cout << i <<", ";
}
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  vector<int>v1 (mynumbers, mynumbers + 6);
  for_each(v1.begin(), v1.end(), bind2nd(plus<int>(),1)); //LINE I
  for_each(v1.rbegin(), v1.rend(),printer); //LINE II
  return 0;
}

the program outputs 2, 5, 7, 8, 10, 9,
runtime error at LINE I
compilation error in LINE I
the program outputs 8, 9, 7, 6, 4, 1,
the program outputs 1, 4, 6, 7, 8,
compilation error in LINE II

What happen if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  bool operator <(const Pocket & _Right)const
  {
    return value<_Right.value;
  }
  bool operator <(const int & _Right) const
  {
    return value < _Right;
  }
  operator int () const
 {
   return value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer(Pocket i)
{
  cout << i <<", ";
}
int
main()
{
  Pocket mynumbers1[] = {4, 9, 1, 6};
  int mynumbers2[] = {4, 1, 4, 5};
  vector<Pocket>v1 (7, 0);
  sort (mynumbers2, mynumbers2 + 4);
  sort (mynumbers1, mynumbers1 + 4); //LINE I
  set_intersection(mynumbers1, mynumbers1 +3, mynumbers2, mynumbers2 +3, v1.begin()); //LINE II
  for_each(v1.begin(), v1.end(),printer);
  return 0;
}

compilation error in LINE II
the program outputs 4, 1,
runtime error at LINE II
compilation error in LINE I
the program outputs 1, 4, 0, 0, 0, 0, 0,
the program outputs 0, 0, 0, 0, 0, 0, 0,

What happen if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  operator int ()const
  {
    return value;
  }
  bool operator <(const Pocket & _Right) const
  {
    return value < _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer(Pocket i)
{                                //LINE I
   cout << i <<", ";
}
struct Add:public binary_function<Pocket, Pocket, Pocket>
{
  Pocket operator() (const Pocket & _Left, const Pocket & _Right)const
  {
    return _Left + _Right;
  }
};
int
main()
{
  Pocket mynumbers1[] = {8, 9, 7, 6, 4, 1};
  vector<Pocket>v1 (mynumbers1, mynumbers1 + 6);
  vector<Pocket> v2(6,0);
  transform(v1.begin(),v1.end(), v2.begin(),bind2nd(Add(), 1)); //LINE II
  for_each(v2.rbegin(), v2.rend(),printer);
  return 0;
}

runtime error at LINE I
compilation error in LINE I
the program outputs 2, 5, 7, 8, 10, 9,
the program outputs 0, 0, 0, 0, 0, 0,
the program outputs 9, 10, 8, 7, 5, 2,
compilation error in LINE II

What happen if you try to compile and run this program?

#include <deque>
#include <iostream>
#include <algorithm>
#include <set>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  bool operator < (const Pocket & _Right)const
  {
    return value < _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
int
main()
{
  Pocket mynumbers1[] = {8, 9, 7, 6, 4, 1};
  Pocket mynumbers2[] = {Pocket(3), Pocket(2),Pocket(4), Pocket(1)};
  deque<Pocket> d1(mynumbers1, mynumbers1 + 6);
  set<Pocket> s1(mynumbers1, mynumbers1 + 6);
  sort(d1.begin(), d1.end());
  sort(mynumbers1, mynumbers1 +5);
  sort(mynumbers2, mynumbers2 + 4);
  cout << includes(d1.begin(), d1.end(), mynumbers1, mynumbers1 +4)<<", " //LINE I
      <<includes(s1.begin(), s1.end, mynumbers2,mynumbers2 + 3); //LINE II
  return 0;
}

runtime error at LINE I
compilation error in LINE II
compilation error in LINE I
the program outputs 8, 9, 7, 6, 3, 2, 4
the program outputs 1, 0
the program outputs 0, 1

What happen if you try to compile and run this program?

#include <deque>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
void
printer(int i)
{
  cout << i <<", ";
}
struct multiAdd:public binary_function<int, int, int>
{
  int operator()(const int & _Left, const int & _Right)const
  {
    return 2 *(_Left + _Right);
  }
};
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  deque<int> d1(mynumbers, mynumbers + 6);
  deque<int>d2(6); //LINE I
  transform (d1.begin(), d1.end(), d2.begin(), bind2nd(multiAdd(), 1)); //LINE II
  for_each(d2.begin(), d2.end(), printer);
  return 0;
}

the program outputs 18, 20, 16, 14, 10, 4,
runtime error at LINE I
the program outputs 4, 10, 14, 16, 18, 20,
compilation error in LINE I
the program outputs 32, 36, 28, 24, 16, 4,
compilation error in LINE II

What happen if you try to compile and run this program?

#include <deque>
#include <iostream>
#include <algorithm>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  bool operator <(const Pocket & _Right) const
  {
    return value < _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer(Pocket i)
{
  cout << i <<", ";
}
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  deque<Pocket> d1(mynumbers, mynumbers +6);
  d1.push_back(4); //LINE I
  deque<Pocket> ::iterator it = lower_bound(d1.begin(), d1.end(), 3); //LINE II
  for_each(it, d1.end(), printer);
  return 0;
}

compilation error in LINE I
the program outputs 8, 9, 7, 6, 4, 1,
the program outputs 8, 9, 7, 6, 4, 4,
the program outputs 8, 9, 7, 6, 4, 1, 4,
compilation error in LINE I
runtime error at LINE I

What happen if you try to compile and run this program?

#include <deque>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  bool operator > (const Pocket & _Right) const
  {
    return value > _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer(Pocket i)
{
  cout << i <<", ";
}
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  deque<Pocket> d1(mynumbers, mynumbers +6);
  sort (d1.begin(), d1.end(), greater<Pocket>()); //LINE I
  deque<Pocket> ::iterator it = lower_bound(d1.begin(), d1.end(), 6,greater<Pocket>()); //LINE II
  for_each(it, d1.end(), printer);
  return 0;
}

runtime error at LINE II
runtime error at LINE I
compilation error in LINE II
the program outputs 6, 4, 1,
the program outputs 8, 9, 7, 6,
the program outputs 4, 1,
compilation error in LINE I

What happen when you attempt to compile and run the following code?

#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
template<typename T> class Pocket
{
  T value;
public:
  Pocket(T value):value(value){}
  T getValue()const
  {
    return value;
  }
  bool operator<(const Pocket & _Right)const
  {
    return value <_Right.value;
  }
};
template<typename T>
  ostream & operator<<(ostream & stream, const Pocket<T>&pocket)
  {
    stream << pocket.getValue();
    return stream;
  }
void
printer(Pocket<double> i)
{
  cout << i <<", ";
}
  bool
  Compare(const Pocket<double>& _Left, const Pocket<double> & _Right)
  {
    return int (_Left.getValue()) <int(_Right.getValue());
  }
int
main()
{
  double mynumbers[] = {1.11, 3.13, 2.12, 5.15, 6.16, 1.15};
  vector <double> v1 (mynumbers, mynumbers + 6); //LINE I
  stable_sort(v1.begin(), v1.end(), Compare); //LINE II
  for_each(v1.begin(),v1.end(), printer);
  return 0;
}

the program outputs 1.11, 3.13, 2.12, 5.15, 6.16, 1.15,
the program outputs 1.11, 2.12, 3.13, 5.15, 6.16, 1.15,
runtime error at LINE II
compilation error in LINE II
the program outputs 1.11, 1.15, 2.12, 3.13, 5.15, 6.16,
compilation error in LINE I
runtime error at LINE II

What happen when you attempt to compile and run the following code?

#include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
#include <set>
using namespace std;
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  vector<int>v1 (mynumbers, mynumbers + 6);
  deque<int>d1 (mynumbers, mynumbers + 6);
  set<int>s1 (mynumbers, mynumbers + 6);
  vector<int>::iterator found = find(v1.begin(), v1.end(), 3);
  if(found != v1.end())
    cout << "found"<<", ";
  cout << find (d1.begin(), d1.end(),9)<<", "; //LINE I
  cout << find (s1.begin(), s1.end(), 6); //LINE II
  return 0;
}

runtime error at LINE I
compilation error in LINE I
program output: found, 8, 9, 7, 6, 4, 1, 1, 4, 6, 7, 8, 9,
program output: 9, 6,
compilation error in LINE II
program output: 8, 9, 7, 6, 4, 1, 1, 4, 6, 7, 8, 9,

What happens if you try to compile and run this program?

#include <iostream>
using namespace std;
int
main()
{
  cout <<31.23<<", ";
  cout.setf(ios::hex, ios::basefield);
  cout.setf(ios::showbase); //LINE I
  cout << 31.23 <<", ";
  cout.unsetf (ios::showbase); //LINE II
  cout <<63.23 <<", ";
  return 0;
}

compilation error in LINE II
compilation error in LINE I
runtime error at LINE I
the program outputs 31.23, 31.23, 63.23,
the program outputs 31.23, 037.27, 77.27,
the program outputs 31.23, 31.27, 77.27,

What happens if you try to compile and run this program?

#include <iostream>
using namespace std;
template<typedef T> //LINE I
  class Pocket
{
public:
  T value;
  Pocket(T value)
  {
  }; //LINE II
};
int
main()
{
  Pocket<double> a(7);
  cout << a.value<<endl;
  return 0;
}

the program outputs 0
compilation error in LINE II
runtime error at LINE II
the program outputs 7
compilation error in LINE I
the program outputs 7.000

What happens if you try to compile and run this program?

#include <iostream>
#include <string>
using namespace std;
template<class Ty> class Pocket
{
  Ty value;
public:
  Pocket(){}
  Pocket (Ty value);
  Ty getValue()
  {
    return value;
  }
  void add (Ty _Right)
  {
    value += _Right;
  }
  template<class Tx> Tx get(Tx _Right)
  {
    return (Tx) (value) + _Right; //LINE I
  }
  friend ostream & operator << (ostream & _os, const Pocket<Ty> &value)
  {
    _os <<value.value;
    return _os;
  }
};
template<class T> Pocket<T> ::Pocket (T value):value (value){}
int
main()
{
  Pocket<int> a(3);
  cout << a <<", ";
  cout <<a.get <double> (2);
  return 0;
}

program output: 3, 5
program output: 3, 3
program output: 3, 6
compilation error in LINE II
compilation error in LINE I

What happens if you try to compile and run this program?
```
#include <iostream>
using namespace std;
int
main()
{
  cout <<31<<", ";
  cout.setf(ios::hex); //LINE I
  cout << 31 <<", ";
  cout.setf(ios::showbase, ios::basefield); //LINE II
  cout <<63 <<", ";
  return 0;
}
```
- compilation error in LINE II
- runtime error at LINE I
- the program output: 31, 31, ,
- the program output: 31, 31, 63
- compilation error in LINE I
- the program output: 31, 31, 3f,

What will happens when attempt to compile and run the following code?

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 1, 1, 6, 6};
  vector <int> v(mynumbers, mynumbers + 8);
  vector<int>::iterator it = search_n(v.begin(), v.end(),2,1); //LINE I
  cout << it - v.begin() <<", "; //LINE II
  return 0;
}

the program output: 1,
compilation error in LINE I
runtime error at LINE I
the program output: 8,
the program output: 4,
compilation error in LINE II

What happens if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value):value(value){}
  int getValue()const
  {
    return value;
  }
  bool operator <(const Pocket & _Right) const
  {
    return value <_Right.value;
  }
  bool operator <(const int & _Right)const
  {
    return value <_Right;
  }
  operator int () const
  {
    return value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer (Pocket i)
{
  cout << i <<", ";
}

int
main()
{
  Pocket mynumbers1[] = {8, 9, 7, 6};
  int mynumbers2[] = {4, 1, 4, 5};
  vector<Pocket> v1(7, 0);
  sort(mynumbers2, mynumbers2 + 4);
  sort(mynumbers1, mynumbers1 + 4); //LINE I
  set_symmetric_difference(mynumbers1, mynumbers1 + 3, mynumbers2, mynumbers2 + 3, v1.begin()); //LINE II
  for_each(v1.begin(), v1.end(), printer);
  return 0;
}

compilation error in LINE II
compilation error in LINE I
the program output: 1, 4, 4, 6, 7, 8,
the program output: 1, 4, 4, 6, 7, 8, 0,
runtime error at LINE I
the program output: 4, 8, 3, 1,

What happens when you attempt to compile and run the following code ?

#include <iostream>
#include <map>
#include <string>
using namespace std;
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  string words[] = {"eight", "nine", "seven", "six", "four", "one"};
  map<int, string>m;
  for(int i=0; i<6;i++)
    m.insert(pair<int, string>(mynumbers[i], words[i])); //LINE I
 if(m[2].value =="seven") //LINE II
   cout<<"seventh element, ";
 for(map <int, string>::iterator i = m.begin(); i != m.end(); i++)
   cout<< i->second << ", ";
 cout<<m.size(); //LINE III
 return 0;
}

compilation error in LINE III
compilation error in LINE II
program outputs: one, , four, six, seven, eight, nine,
program outputs: seven element, one, , four, six, seven, eight, nine, 7
program outputs: one, , four, six, seven, eight, nine, 7
runtime error at LINE II
compilation error in LINE II

What happens if you try to compile and run this program ?

#include <iostream>
using namespace std;
void
f(double a) //LINE II
{
  cout << 2 + a <<endl;
}
template <class A>void
  f(A & a) //LINE I
  {
    cout << 1 + a << endl;
  }

int
main()
{
  double a = 1.5;
  f(a); //LINE III
  return 0;
}

compilation error in LINE II
the program outputs 1.5
runtime error at LINE II
the program outputs 2.5
the program outputs 3.5
compilation error in LINE I

What will happens when you attempt to compile and run the following code ?

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int
main()
{
  int mynumbers[] = {8, 9, 7, 6, 4, 1};
  vector <int>v (mynumbers, mynumbers + 6);
  vector <int>::iterator it;
  int m1[] = { 7, 6, 4 };
  it = find_end (v.begin (), v.end(), m1,m1 + 3); //LINE I
  if (it != v.end ())
  cout<<"Found at position: " << it - v.begin () << endl; //LINE II
  return 0;
}

compilation error in LINE I
program outputs: Found at position:
runtime error at LINE I
compilation error in LINE II
program outputs: Found at position: 1
program outputs: Found at position: 2

Which sentences are 100% true about the code below(multiple choice)when control reaches return:
```
#include <vector>
#include <iostream>
using namespace std;
int
main()
{
  vector <int>v1 (10, -1);
  vector <int>v2;
  v2.reserve (10);
  for(unsigned i = 0; i<10; i++)
    {
      v2.push_back(i);
    }
  cout<< v2[0] << ", " << v1[0];
  return 0;
}
```
- both vectors v1 and v2 have the same capacity
- program outputs: -1, 10
- program outputs: -1, 0
- program outputs: 0, -1
- value returned by size() is the same for vectors v1 and v2
- program outputs: 0, 0

What will happens when you attempt to compile and run the following code ?

#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
void
printer (int i)
{
   cout << i <<", ";
}
int
main()
{
  int mynumbers1[] = {8, 9, 7, 6 };
  int mynumbers2[] = {4, 1, 4, 5 };
  vector <double>v1 (7);
  sort (mynumbers2, mynumbers2 + 4);
  sort (mynumbers1, mynumbers1 + 4);   //LINE I
  int m1[] = { 7, 6, 4 };
  merge (mynumbers1, mynumbers1 + 2, mynumbers2, mynumbers2 + 2, v1.begin ());  //LINE II
  for_each (v1.begin (), v1.end (), printer);
  return 0;
}

program outputs 1, 4, 6, 7, 0, 0,
compilation error in LINE II
compilation error in LINE I
program outputs 1, 4, 4, 6,
program outputs 1, 4, 6, 7, 0, 0, 0,
runtime error at LINE I

What will happens when you attempt to compile and run the following code assuming that you will enter following sequence: `i j k jk q<enter>`?

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
void 
printer (string i)
{
   cout<<i<<", ";
}
int
main()
{
  vector <string>v1;
  string s;
  do
   {
      cin >> s;
      v1.push_back(s);   //LINE I
    }
  while (s != "q" && cin.good()); // LINE II
  for_each (v1.begin (), v1.end(), printer);
  return 0;
}

compilation error in LINE II
program outputs i, j, k, jk, q, q,
program outputs i, j, k, jk,
compilation error in LINE I
program outputs i, j, k, jk, q,
runtime error at LINE I

What happens if you try to compile and run this program ?
```
#include <iostream>
using namespace std;
template < class T > void
f (T & a)           //LINE I
{
  cout << 2 * a <<endl;
}
int
main()
{
  int a = 2;
  f(a);     //LINE III
  return 0;
}
```
- compilation error in LINE I
- runtime error at LINE I
- the program outputs 2
- compilation error in LINE II
- the program outputs 4
- the program outputs 1
Which of the following examples show(s) the proper way to create a new queue container assuming all necessary declarations have been performed. Choose all that apply:
- queue q;
- list 1; queue q(1);
- array_list 1; queue q(1);
- deque d; queue q(d);
- vector v; queue q(v);

What happens when you attempt to compile and run the code?

#include <iostream>
#include <map>
using namespace std;
int
main()
{
  int mynumbers[] = { 8, 9, 7, 6, 4, 1, 4 };
  string words[] = { "eight", "nine", "seven", "six", "four", "one", "four" };
  map < int, string > m;
  for (int i = 0; i < 7; i++)
    {
       m.insert (pair < int, string > (mynumbers[i], words[i])); //LINE I
    }
  if (m.count (4) == 2)
    m.erase(2);           //LINE II
  for(map <int, string>::iterator i = m.begin(); i != m.end(); i++)
   {
      cout << i->first << ", ";
   }
  return 0;
}

program outputs: 1, 6, 7, 8, 9, 4
program outputs: 1, 4, 6, 7, 8, 9, 4,
compilation error in LINE II
program outputs: 1, 4, 7, 8, 8, 9, 4,
compilation error in LINE I
program outputs: 1, 4, 6, 7, 8, 9,
runtime error at LINE II

What happens if you try to compile and run this program?

#include <iostream>
using namespace std;
int
main()
{
  cout << 31 << ", ";
  cout.setf (ios::hex, ios::basefield);
  cout.setf (ios::showbase); //LINE I
  cout << 31 << ", ";
  cout.unsetf (ios::showbase); //LINE II
  cout << 63 << ", ";
  return 0;
}

the program outputs 31, 31, 3f,
compilation error in LINE II
runtime error at LINE I
compilation error in LINE I
the program outputs 31, 31, 63
the program outputs 31, 0x1f, 3f,

What will happens when you attempt to compile and run the following code?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
int Mul (int & _Left)
{
  if(_Left <= 3)
     return 2 * _Left;
  else
     return 6;
  }
int
main()
{
  int mynumbers[] = { 8, 9, 7, 6, 4, 1, 4 };
  vector < int > v1 (mynumbers, mynumbers + 7);
  vector < int >v2 (7);
  transform (v1.begin (), v1.end(), v2.begin (), ptr_fun (Mul)); //LINE I
  vector < int >::iterator it = find_if (v2.begin (), v2.end (), bind2nd (equal_to < int >(), 4)); //LINE II
  cout << *it <<endl; //LINE III
  return 0;
}

the program outputs: 0
runtime error at LINE I
compilation error in LINE I
the program outputs 3
compilation error in LINE III
compilation error in LINE II
the program outputs 4

What happens when you attempt to compile and run the code?

#include <iostream>
#include <algorithm>
#include <vector> 
#include <deque> 
#include <set> 
using namespace std;
void
myprint (int i) 
{
   cout << i << ", ";
}
int
main()
{
  int mynumbers[] = { 8, 9, 7, 6, 4, 1 };
  vector < int > v1 (mynumbers, mynumbers + 6);
  v1.pop_back ();    
  v1.pop_back ();
  v1.pop_back ();
  set < int > s1 (mynumbers, mynumbers + 6);
  deque < int > d1 (mynumbers, mynumbers + 6);
  v1.pop_front ();    //LINE I
  v1.pop_front ();
  v1.pop_front ();
  for_each (v1.begin (), v1.end (), myprint);  //LINE II
  for_each (s1.begin (), s1.end (), myprint);
  for_each (d1.begin (), d1.end (), myprint);
  return 0;
}

compilation error in LINE I
program outputs 8, 9, 7, 1, 4, 6, 7, 8, 9, 6, 4, 1,
compilation error in LINE II
runtime error at LINE I
program outputs: 8, 9, 7, 1, 4, 6, 7, 8, 9,
program outputs: 8, 9, 7, 6, 4, 1, 4, 6, 7, 8, 9, 6, 4, 1,

What happens if you try to compile and run this program?

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
class A
{
  int a;
public:
  A (int a):a (a)
  {
  }
  int getA () const
  {
    return a;
  }
  void setA (int a)
  {
  this->a = a;
  }
  bool operator == (const A & b) const
  {
    return a == b.a;
  }
};
int
main()
{
  cout << 31 << ", ";
  cout.setf (ios::hex, ios::basefield);
  cout.setf (ios::showbase); //LINE I
  cout << 31 << ", ";
  cout.unsetf (ios::showbase); //LINE II
  cout << 63 << ", ";
  return 0;
}

the program outputs 31, 31, 3f,
compilation error in LINE II
runtime error at LINE I
compilation error in LINE I
the program outputs 31, 31, 63
the program outputs 31, 0x1f, 3f,

What happens if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <functional>
#include <algorithm>
using namespace std;
template<class T> struct Out
{
  ostream & out;
  Out (ostream & o):out(o){}
  void operator()(const T & val)
  {
    out<<val<<", ";
  }
};
struct Sequence
{
  int start;
  Sequence(int start):start(start){}
  int operator()()
  {
    return start++ % 7;
  }
};

int
main()
{
  vector<int>v1(5);
  generate(v1.rbegin(),v1.rend(),Sequence(8)); //LINE I
  rotate(v1.begin(), v1.begin() + 1, v1.end()); //LINE II
  for_each(v1.begin(), v1.end(),Out<int>(cout));
  return 0;
}

the program outputs 5, 4, 3, 2, 6,
compilation error in LINE II
the program outputs 4, 3, 2, 1, 5,
runtime error at LINE I
the program outputs 4, 3, 2, 1, 6,
compilation error in LINE I

What happens if you try to compile and run this program?

#include <iostream>
using namespace std;
int
main()
{
  cout<<31<<", ";
  cout.setf(ios::oct, ios::basefield);
  cout.setf(ios::showbase); //LINE I
  cout<<31<<", ";
  cout.unsetf(ios::showbase); //LINE II
  cout<<63<<", ";
  return 0;
}

compilation error in LINE I
the program outputs 31, 31, 77,
the program outputs 31, 31, 63,
runtime error at LINE I
compilation error in LINE II
the program outputs 31, 037, 77,

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: 4 5 6 <enter>?
```
#include <iostream>
#include <string>
using namespace std;
int
main()
{
  string s;
  getline(s); //LINE I
  cout << s <<", "<< s <<", "<<endl; //LINE II
  return 0;
}
```
- runtime error at LINE I
- compilation error in LINE I
- the program outputs 4 5 6, 4 5 6,
- the program outputs 4 5 6 4 5 6,
- compilation error in LINE II
- the program outputs 4, 5, 6, 4, 5, 6,

What will happen when you attempt to compile and run the following code?

#include <deque>
#include <iostream>
#include <algorithm>
using namespace std;
void
printer (int i)
{
  cout << i <<", ";
}

int
main()
{
  int mynumbers[]={8, 9, 7, 6, 4, 1};
  deque<int>d1(mynumbers, mynumbers + 6);
  deque<int>::iterator it = lower_bound(d1.begin(), d1.end(), 3);
  d1.push_back(4); //LINE I
  for_each(it, d1.end(), printer); //LINE II
  return 0;
}

the program outputs 8, 9, 7, 6, 4, 4,
runtime error at LINE I
the program outputs 8, 9, 7, 6, 4, 1,
compilation error in LINE II
the program outputs 8, 9, 7, 6, 4, 1, 4,
compilation error in LINE I

What will happen when you attempt to compile and run the following code?

#include <vector>
#include <queue>
#include <iostream>
using namespace std;
int
main()
{
  int t[]={1, 5, 1, 4, 2};
  vector<int>v (t, t + 5);
  priority_queue<int> q(v.begin(),v.end()); //LINE I
  q.push(4); //LINE II
  cout << q.top() <<", ";
  q.push(3);
  cout << q.top() << endl;
  return 0;
}

program outputs: 4, 4
runtime error at LINE II
compilation error in LINE II
program outputs: 5, 5
compilation error in LINE I
program outputs: 4, 3

What happens if you try to compile and run this program?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
class Pocket
{
  int value;
public:
  Pocket(int value): value(value){}
  int getValue() const
  {
    return value;
  }
  operator int ()const
  {
    return value;
  }
  bool operator<(const Pocket & _Right)const
  {
    return value < _Right.value;
  }
};
ostream & operator << (ostream & stream, const Pocket & pocket)
{
  stream << pocket.getValue();
  return stream;
}
void
printer (Pocket i)
{                //LINE I
  cout << i <<", ";
}

int
main()
{
  Pocket mynumbers1[] = {8, 9, 7, 6, 4, 1};
  Pocket mynumbers2[] = {8, 9, 1, 2, 2, 1};
  vector<Pocket>v1(mynumbers1, mynumbers1 + 6);
  vector<Pocket> v2(mynumbers2, mynumbers2 + 6);
  vector <Pocket> v3(6, 0);
  transform(v1.begin(), v1.end(), v2.begin(), v3.begin(),minus<Pocket> ()); //LINE II
  for_each(v1.rbegin(), v1.rend(), printer);
  return 0;
}

runtime error at LINE I
the program outputs 0, 0, 0, 0, 0, 0,
the program outputs 0, 3, 5, 6, 8, 7,
compilation error in LINE I
compilation error in LINE II
the program outputs 1, 4, 6, 7, 9, 8,

What happen if you try to compile and run this program?

#include <iostream>
using namespace std;
template <class T> class Pocket
{
public:
  T value;
  Pocket(T value);
};
template <class T> Pocket<T>::Pocket(T value):value(value)
{
} //LINE I
int
main()
{
  Pocket<double> a(7); //LINE II
  cout << a.value <<endl;
  return 0;
}

the program outputs 7.0000
the program outputs 7
the program outputs 0
compilation error in LINE II
compilation error in LINE I
runtime error at LINE II

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: false true true<enter>?
```
#include <iostream>
using namespace std;
int
main()
{
  bool c1, c2, c3;
  cin >> boolalpha >> c1 >> c2 >> c3;
  cout << boolalpha << c3 <<", "<< c1 <<", " << c2 <<", "<<endl; //LINE I
  return 0;
}
```
- the program outputs true, false, true,
- runtime error at LINE I
- the program outputs false, false, true,
- compilation error in LINE I
- the program outputs 1, 0, 1,

CPP : All Parts

CPP – Advanced Programming in C++ : All Parts
M1	M4	M7
M2	M5	M8
M3	M6	M9
Summary Test
Final Test

Advanced C++ | Final Test

What happen if you try to compile and run this program?

Which methods from std::deque class can be used to check if there are element in the container. Choose all that apply:

What will happen when you attempt to compile and run the following code?

What happen if you try to compile and run this program?

What will happen when you attempt to compile and run the following code?

What will happen when you attempt to compile and run the following code?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

Which of the following is are legal variable names?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen if you try to compile and run this program?

What happen when you attempt to compile and run the following code?

What happen when you attempt to compile and run the following code?

What happens if you try to compile and run this program?

What happens if you try to compile and run this program?

What happens if you try to compile and run this program?

What happens if you try to compile and run this program?

What will happens when attempt to compile and run the following code?

What happens if you try to compile and run this program?

What happens when you attempt to compile and run the following code ?

What happens if you try to compile and run this program ?

What will happens when you attempt to compile and run the following code ?

Which sentences are 100% true about the code below(multiple choice)when control reaches return:

What will happens when you attempt to compile and run the following code ?

What will happens when you attempt to compile and run the following code assuming that you will enter following sequence: i j k jk q<enter>?

What happens if you try to compile and run this program ?

Which of the following examples show(s) the proper way to create a new queue container assuming all necessary declarations have been performed. Choose all that apply:

What happens when you attempt to compile and run the code?

What happens if you try to compile and run this program?

What will happens when you attempt to compile and run the following code?

What happens when you attempt to compile and run the code?

What happens if you try to compile and run this program?

What happens if you try to compile and run this program?

What happens if you try to compile and run this program?

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: 4 5 6 <enter>?

What will happen when you attempt to compile and run the following code?

What will happen when you attempt to compile and run the following code?

What happens if you try to compile and run this program?

What happen if you try to compile and run this program?

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: false true true<enter>?

What will happens when you attempt to compile and run the following code assuming that you will enter following sequence: `i j k jk q<enter>`?

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: `4 5 6 <enter>`?

What will happen when you attempt to compile and run the following code assuming that you will enter following sequence: `false true true<enter>`?