Review the following code (note the variable name):
let age = 32;
age = age + 1;
console.log(Age);
As a result of its execution, the following should appear in the console:
undefined
32
- error message:
"uncaught ReferenceError: Age is not defined"
.
33
Answers Explanation & Hints:
In the code snippet provided, there is a mismatch in the variable names. The variable age is declared and assigned the value 32 . Then, it is incremented by 1 using age = age + 1; . However, when attempting to console.log(Age); , it refers to a variable Age with a capital “A”, which has not been declared or assigned any value.
JavaScript is case-sensitive, so Age and age are considered as separate variables. Since Age is not defined, it will result in an “uncaught ReferenceError” when trying to access it. |
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