What is the output of the following program?

#include <stdio.h>
int main()
{
    int var;
    var = 1; 
    var = 2;
/*  var = 3; */
    print("%d", var);
    return 0;
}

Explanation & Hints:

The output of the provided C program will be 2. Here’s a step-by-step explanation:

int var; declares an integer variable named var.
var = 1; sets the value of var to 1.
var = 2; then changes the value of var to 2.
/* var = 3; */ is commented out and thus has no effect on the program’s execution.
print("%d", var); should be printf("%d", var); to correctly compile in C. Assuming this is a typo and should be printf, it will print the current value of var, which is 2.

Therefore, the correct output, assuming the typo is corrected to printf, is 2.

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