What is the value of the var variable at the end of the following snippet?

To find the value of the variable var at the end of the given C code snippet, let’s walk through the code step by step:

Initialization:

int var;
var = 2;

Here, var is initialized to 2.

First Update:

var = var * var;

The value of var is squared, so 2 * 2 = 4. Now var equals 4.

Second Update:

var = var + var;

The value of var is added to itself, so 4 + 4 = 8. Now var equals 8.

The lines within the comment block are not executed, as they are commented out:

/*
var = var / var;
var = var % var;
*/

Let’s break down the operations step-by-step:

int var;
var = 2;
var = var * var;
var = var + var;
var = var / var;
var = var % var;

1. Initial value:
   • var = 2
2. Multiplication:
   • var = var * var
   • var = 2 * 2
   • var = 4
3. Addition:
   • var = var + var
   • var = 4 + 4
   • var = 8
4. Division:
   • var = var / var
   • var = 8 / 8
   • var = 1
5. Modulo:
   • var = var % var
   • var = 1 % 1
   • var = 0 (since any number modulo itself is 0)

So, the value of var at the end of the snippet is 0.