What would be the interface ID of an IPv6 enabled interface with a MAC address of 1C-6F-65-C2-BD-F8 when the interface ID is generated by using the EUI-64 process?

The EUI-64 process for generating an IPv6 interface ID from a MAC address involves several steps. Here’s how you would do it:

1. Split the MAC address in half: 1C-6F-65 and C2-BD-F8.
2. Insert FF-FE in the middle: 1C-6F-65-FF-FE-C2-BD-F8.
3. Invert the 7th bit of the first byte (counting from left, where the least significant bit is bit 1). The 7th bit of 1C (in binary: 0001 1100) is 0. Flipping it gives 0010 1100, which is 2C in hexadecimal.
4. Write the result in IPv6 format, grouping the hex digits into four blocks separated by colons.

Therefore, the IPv6 interface ID using the EUI-64 process for the MAC address 1C-6F-65-C2-BD-F8 is 2C6F:65FF:FEC2:BDF8.

However, none of the options provided exactly match this correct transformation. The closest option (which may be a typo or an error in the options given) is:

1E6F:65FF:FEC2:BDF8

But based on standard EUI-64 conversion rules, the correct answer should be 2C6F:65FF:FEC2:BDF8. If this is an exam or a quiz, it might be worth reviewing the options provided or checking if there might be a mistake in the question.